"""
You are given an m x n integer grid accounts where accounts[i][j] is the amount of money the i​​​​​​​​​​​th​​​​ customer has in the
j​​​​​​​​​​​th​​​​ bank. Return the wealth that the richest customer has.

A customer's wealth is the amount of money they have in all their bank accounts. The richest customer is the customer
that has the maximum wealth.



Example 1:

Input: accounts = [[1,2,3],[3,2,1]]
Output: 6
Explanation:
1st customer has wealth = 1 + 2 + 3 = 6
2nd customer has wealth = 3 + 2 + 1 = 6
Both customers are considered the richest with a wealth of 6 each, so return 6.
Example 2:

Input: accounts = [[1,5],[7,3],[3,5]]
Output: 10
Explanation:
1st customer has wealth = 6
2nd customer has wealth = 10
3rd customer has wealth = 8
The 2nd customer is the richest with a wealth of 10.
Example 3:

Input: accounts = [[2,8,7],[7,1,3],[1,9,5]]
Output: 17


Constraints:

m == accounts.length
n == accounts[i].length
1 <= m, n <= 50
1 <= accounts[i][j] <= 100
"""


class Solution:
    def maximumWealth(self, accounts) -> int:
        """
        :param accounts:
        :type accounts list[list[int]]
        :return:
        """

        maximum_wealth = 0
        for i in range(len(accounts)):
            customer_wealth = sum(accounts[i])
            maximum_wealth = max(customer_wealth, maximum_wealth)

        return maximum_wealth
